In mathematics, the complex conjugate root theorem states that if P is a polynomial in one variable with real coefficients, and a + bi is a root of P with a and b real numbers, then its complex conjugate a − bi is also a root of P. It follows from this (and the fundamental theorem of algebra) that, if the degree of a real polynomial is odd, it must have at least one real root. That fact can also be proved by using the intermediate value theorem.

Examples and consequences

a+bi and a−bi , they form a quadratic c , this becomes

Corollary on odd-degree polynomials

It follows from the present theorem and the fundamental theorem of algebra that if the degree of a real polynomial is odd, it must have at least one real root. This can be proved as follows. This requires some care in the presence of multiple roots; but a complex root and its conjugate do have the same multiplicity (and this lemma is not hard to prove). It can also be worked around by considering only irreducible polynomials; any real polynomial of odd degree must have an irreducible factor of odd degree, which (having no multiple roots) must have a real root by the reasoning above. This corollary can also be proved directly by using the intermediate value theorem.

Proof

One proof of the theorem is as follows: Consider the polynomial where all ar are real. Suppose some complex number ζ is a root of P, that is. It needs to be shown that as well. If P(ζ  ) = 0, then which can be put as Now and given the properties of complex conjugation, Since it follows that That is, Note that this works only because the ar are real, that is,. If any of the coefficients were non-real, the roots would not necessarily come in conjugate pairs.